Mysql subtract two columns

Mysql subtract two columns DEFAULT

How to subtract two subquery in a single query in sql server

[I hope this isn’t a duplicate post… I posted this an hour ago and it didn’t show up, so I’ll try again]

@John – the GROUP BY won’t work because the ‘b.tot_sales_rs’ is not part of the result set — it’s included in the aggregate function only.

@Abhijit – I can’t get my head around the problem, so I am offering a different query structure. Alun’s version works until you introduce the complication of duplicate data rows in the table. This is a different approach, which I tested using MySQL:

select TA.branch, TA.dt as a_dt, TB.dt as b_dt,
TA.sales as sales_1, TB.sales as sales_2,
TA.sales –
CASE
WHEN TB.sales is NULL then 0
ELSE TB.sales
END as total_salesdiff
from
(select a.branch,a.dt,sum(a.tot_sales) as sales
from
(select DISTINCT branch, dt, tot_sales from forex) a
where a.dt = date ‘2011-03-24’
group by a.branch, a.dt
) TA
LEFT OUTER JOIN
(select b.branch,b.dt,sum(b.tot_sales) as sales
from
(select DISTINCT branch, dt, tot_sales from forex) b
where b.dt = date ‘2011-03-24’ – interval ‘1’ day
group by b.branch, b.dt
) TB
on (TA.branch = TB.branch)
and(TA.dt = TB.dt + interval ‘1’ day)
order by TA.branch, TA.dt, TB.dt
;

Here’s how this query works:
(1) use DISTINCT on the base table to eliminate duplicates
(2) apply a date filter
(3) sum the sales by branch and date (only one date here)
(4) repeat (1)-(3) for the previous day
(5) join the results of (3) and (4), using an OUTER JOIN to preserve data
(6) compute the sales difference, using zero when there is no previous day’s data
(7) sort the results by branch and date

I included the total sales for each date just to verify my calculations. Also, I used standard ANSI date construction — you’ll need to apply the “convert()” function from the other query version for your date format.

Also — this does not cover the case where there is sales data for ‘2011-03-23’ but no sales data for ‘2011-03-24’.

good luck,
–bryan

Sours: https://www.toolbox.com/tech/oracle/question/how-to-subtract-two-subquery-in-a-single-query-in-sql-server-032411/

How to subtract the same amount from all values in a column with MySQL?


Let us first create a table −

mysql> create table DemoTable741 (Number int); Query OK, 0 rows affected (0.61 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable741 values(70); Query OK, 1 row affected (0.18 sec) mysql> insert into DemoTable741 values(55); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable741 values(89); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable741 values(79); Query OK, 1 row affected (0.35 sec) mysql> insert into DemoTable741 values(34); Query OK, 1 row affected (0.17 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable741;

This will produce the following output -

+--------+ | Number | +--------+ | 70 | | 55 | | 89 | | 79 | | 34 | +--------+ 5 rows in set (0.00 sec)

Following is the query to subtract the same amount from all the values in a column −

mysql> select (Number-20) AS Result from DemoTable741;

This will produce the following output -

+--------+ | Result | +--------+ | 50 | | 35 | | 69 | | 59 | | 14 | +--------+ 5 rows in set (0.00 sec)
Sours: https://www.tutorialspoint.com/how-to-subtract-the-same-amount-from-all-values-in-a-column-with-mysql
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How to do MINUS/EXCEPT and INTERSECT in MySQL



Because MySQL does not support MINUS/EXCEPT and INTERSECT, the workaround is to use JOINs to achieve the same effect.

If you want to get hands on with queries in this tutorial, you need to check out this page to prepare data first.

Below are the 4 tables used in this tutorial.

Table 1:

Table 2:

Table 1: with checksum column

Table 2: with checksum column

1. MINUS/EXCEPT

MINUS is an Oracle SQL set operation that selects rows from the first table and then removes rows that are also found in the second table. In Microsoft SQL Server, EXCEPT is the equivalent one to do the same thing.

The standard SQL format is like below.

Oracle:

SELECT * FROMsuppliers_1_md5
MINUS
select * FROMsuppliers_2_md5;

SQL Server:

SELECT * FROMsuppliers_1_md5
EXCEPT
SELECT * FROMsuppliers_2_md5;

Diagram below shows the query result for Table 1 MINUS/EXCEPT Table 2.

MySQL does not support MINUS/EXCEPT, the workaround is to use LEFT JOIN. Because MINUS/EXCEPT compares every column between Table 1 and Table 2, so the join clause needs to contain all 4 columns SupplierID, CompanyName, ContactName, ContactTitle. The where clause picks null values in SupplierID in Table 2, which limits to rows exist in Table 1 only.

SELECTt1.* FROMsuppliers_1ASt1
LEFTJOINsuppliers_2ASt2ON
t1.SupplierID=t2.SupplierID
ANDt1.CompanyName=t2.CompanyName
ANDt1.ContactName=t2.ContactName
ANDt1.ContactTitle=t2.ContactTitle
WHEREt2.SupplierIDISNULL;

Result: 2 rows returned.

In Table 1, there are 2 rows that don't exist in Table 2.

Query below returns the same rows as above, but the join clause only contains 1 column called Checksum. It demonstrates a practical use of function MD5 to generate a checksum value for comparison. Because MINUS/EXCEPT compares/joins all columns between Table 1 and Table 2, if the table has a hundred columns, then values in all these columns need to be compared. In real world applications, it could dramatically increase development and maintenance time and reduce query performance. The best practice is to calculate a checksum value by concatenating all columns as shown here, md5(concat(SupplierID, CompanyName, ContactName, ContactTitle)). Then only 1 column is to be joined.

SELECTt1.* FROMsuppliers_1_md5ASt1
LEFTJOINsuppliers_2_md5ASt2ONt1.checksum=t2.checksum
WHEREt2.SupplierIDISNULL;

Result: 2 rows returned.

2. INTERSECT

INTERSECT returns distinct rows that exist in both tables.

This is the standard format but MySQL does not support the syntax.

SELECT * FROMsuppliers_1_md5
INTERSECT
SELECT * FROMsuppliers_2_md5;

Diagram below shows the query result for Table 1 INTERSECT Table 2.

Below is how MySQL will do INTERSECT by using an inner join. Note that all 4 columns in table 1 are intersected with the 4 columns in table 2.

SELECTt1.* FROMsuppliers_1ASt1
JOINsuppliers_2ASt2ON
t1.SupplierID=t2.SupplierID
ANDt1.CompanyName=t2.CompanyName
ANDt1.ContactName=t2.ContactName
ANDt1.ContactTitle=t2.ContactTitle;

Result: 3 rows returned.

Here EXISTS is used and returns the same rows as above.

SELECT *
FROMsuppliers_1ast1
whereEXISTS(SELECT * FROMsuppliers_2ast2
WHEREt1.SupplierID=t2.SupplierID
ANDt1.CompanyName=t2.CompanyName
ANDt1.ContactName=t2.ContactName
ANDt1.ContactTitle=t2.ContactTitle);

You also can use sub-query with IN keyword to do INTERSECT in MySQL.

SELECT * FROMsuppliers_1
WHERE(SupplierID, CompanyName, ContactName, ContactTitle)
IN(SELECTSupplierID, CompanyName, ContactName, ContactTitleFROMsuppliers_2);

But we still like to use our checksum column for better performance and cleaner SQL code - only compare 1 column rather than intersect 4 columns.

SELECTt1.* FROMsuppliers_1_md5ASt1
JOINsuppliers_2_md5ASt2ONt1.Checksum=t2.Checksum;

Result: 3 rows returned.

EXISTS:

SELECT *
FROMsuppliers_1_md5ast1
whereEXISTS(SELECT * FROMsuppliers_2_md5ast2
WHEREt1.Checksum=t2.Checksum);

IN clause:

SELECT * FROMsuppliers_1_md5
WHEREChecksumIN(SELECTChecksumFROMsuppliers_2_md5);

Happy Coding!



Other tutorials in this category

1. Using Inner Joins to Combine Data from Two Tables

2. Using Outer Joins to Combine Data from Two Tables

3. Another Example for Outer Joins (three tables)

4. Using Self Joins to Combine Data from the Same Table

5. SQL Set Operators - a Visual Guide to UNION, UNION ALL, MIMUS/EXCEPT, INTERSECT

6. Using UNION to Append Result Sets

7. Create working tables to demonstrate how to mimic set operators MINUS, EXCEPT, INTERSECT in MySQL

8. How to Simulate Full Join in MySQL - Part 1: return both matched and unmatched rows

9. How to Simulate Full Join in MySQL - Part 2: return unmatched rows only

10. How to Simulate Full Join in MySQL - Part 3: use UNION to simulate FULL JOIN

11. Use Cross Join to Combine Data in MySQL

12. Differences Between Join and Union

Back to Tutorial Index Page

Sours: http://www.geeksengine.com/database/multiple-table-select/minus-except.php
Adding \u0026 Subtracting Vertical Columns in Excel : MS Excel Tips

Problem:

You have two columns of the date type and you want to calculate the difference between them.

Example:

In the table, there are three columns: , , and . You'd like to calculate the difference between and , or the number of days from to departure inclusively.

The table looks like this:

iddeparturearrival
12018-03-252018-04-05
22019-09-122019-09-23
32018-07-142018-07-14
42018-01-052018-01-08

Solution:

SELECT id, departure, arrival, DATEDIFF(arrival, departure) AS date_difference, DATEDIFF(arrival, departure) + 1 AS days_inclusive FROM travel;

The result is:

iddeparturearrivaldate_differencedays_inclusive
12018-03-252018-04-051112
22019-09-122019-09-231112
32018-07-142018-07-1401
42018-01-052018-01-0834

Discussion:

To count the difference between dates in MySQL, use the function. The difference between and is expressed in days. In this case, the is and the is .

In most cases, though, what you really want is the number of days from the first date to the second date inclusively. You need to add 1 day to the difference: .

Recommended courses:

Recommended articles:

See also:

Sours: https://learnsql.com/cookbook/how-to-calculate-the-difference-between-two-dates-in-mysql/

Two mysql columns subtract

How can we subtract values in MySQL table with the help of LEFT JOIN?


It can be understood with the help of an example in which two tables are having some values and we subtract the values with the help of LEFT JOIN. Here we are taking two tables having the following data −

mysql> Select * from value_curdate; +----+----------+-------+ | Id | Product  | Price | +----+----------+-------+ | 1  | Notebook | 100   | | 2  | Pen      | 40    | | 3  | Pencil   | 65    | +----+----------+-------+ 3 rows in set (0.00 sec) mysql> Select * from value_prevdate; +----+-----------+-------+ | Id | Product   | Price | +----+-----------+-------+ | 1  | Notebook  | 85    | | 2  | Pen       | 34    | | 3  | Pencil    | 56    | | 4  | Colors    | 65    | | 5  | Fevistick | 25    | +----+-----------+-------+ 5 rows in set (0.00 sec)

The above two tables are having the current price and previous price of products respectively. Now the following query, by using LEFT JOIN, will find the difference in price between the same products stored in both the tables.

mysql> Select value_curdate.id, value_curdate.product, value_curdate.price as Curprice,value_prevdate.price as 'prevprice', value_curdate.price-value_prevdate.price as 'Difference' from value_curdate LEFT JOIN value_prevdate ON value_curdate.id = value_prevdate.id ; +----+----------+----------+-----------+------------+ | id | product  | Curprice | prevprice | Difference | +----+----------+----------+-----------+------------+ | 1  | Notebook | 100      | 85        | 15         | | 2  | Pen      | 40       | 34        | 6          | | 3  | Pencil   | 65       | 56        | 9          | +----+----------+----------+-----------+------------+ 3 rows in set (0.00 sec)
Sours: https://www.tutorialspoint.com/How-can-we-subtract-values-in-MySQL-table-with-the-help-of-LEFT-JOIN
MSSQL - SQLServer - How to Calculate Sum of Multiple Columns

mysql subtract two rows from column and places into an alias

I have table with columns: , , .

I'm trying to subtract two rows in column together and put the results into an alias called .

I'm using:

What I get back in consumption alias is simple the same as the original :

what I would like is:

so id 1 = 0 because this is the first date_taken kwh reading so has no need for a consumption value. This is trying to calculate over a year the weekly kwh consumption.

Answer #1:

Just give the table name an alias, and the table inside the correlated subquery a different alias name. Something like this:

SQL Fiddle Demo

This will give you:


Update 1

For the updated sample data, just use inside the correlated subquery with so that the first one will be 0. Like this:

Updated SQL Fiddle Demo

This will give you:

Answered By: Paul Lane

Answer #2:

COALESCE returns the first non null value , so you have to try this query without COALESCE, and see whats the problem

Answered By: Mahmoud Gamal

The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 .

Sours: https://www.py4u.net/discuss/839392

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Sours: https://www.adoclib.com/blog/subtract-values-from-two-columns-in-sql-query.html


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